The horizontal force F = ( 0.30 N/s ) t i – ( 0.50 N/s 2 ) t 2 j is applied to a box that has an initial momentum P = -( 2.0 kgm/s ) i + ( 3.0 kgm/s…

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The horizontal force F = ( 0.30 N/s ) t i – ( 0.50 N/s2 ) t2j is applied to a box that has an initial momentum P = -( 2.0 kg⋅m/s ) i + ( 3.0 kg⋅m/s ) j. What is the momentum of the box at t = 2.0 s ?The post The horizontal force F = ( 0.30 N/s ) t i – ( 0.50 N/s 2 ) t 2 j is applied to a box that has an initial momentum P = -( 2.0 kgm/s ) i + ( 3.0 kgm/s… first appeared on Nursing School Essays.